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Thread: Figuring out the straight length of a flatbar after its been rolled into a circle

  1. #26
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    Re: Figuring out the straight length of a flatbar after its been rolled into a circle

    Flats are easily removed by backrolling using the common power or hand crank slip roll.
    Last edited by hommeacier; 04-22-2017 at 10:14 PM.

  2. #27
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    Re: Figuring out the straight length of a flatbar after its been rolled into a circle

    My mistake. you are correct Broccoli. I was referring to DGM's reply just before yours.

  3. #28
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    Re: Figuring out the straight length of a flatbar after its been rolled into a circle

    Quote Originally Posted by steve45 View Post
    Ummmm...

    Why not just wrap a tape measure around it?
    Because a standard tape measure is made to be used flat. You'd need to use a pi tape to get a correct measurement.

  4. #29
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    Re: Figuring out the straight length of a flatbar after its been rolled into a circle

    Same here. I have a few years in a fab shop and I'm just now starting out on my own. I still have my day job as a jr Project Manager but I plan on starting my own company in a few years. I just turned 20 Friday.

  5. #30
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    Re: Figuring out the straight length of a flatbar after its been rolled into a circle

    The same you figure the flat pattern for any round tube or pipe .
    .
    Outside diameter then minus 1 material thickness times 3.14 / Below chart does not account for weld shrink !
    .
    Then add 1 material thickness for weld shrink /this is only a Typical factor number / weld joint design and welding technique can make a difference also.
    .
    Any measuring tool going around the outside diameter is not going to be accurate. unless its a "Pi Tape''
    better off measuring across 6 equal places and then take average dim' provided it's pretty round .
    .
    For your example:
    Measure outside diameter then minus 1 material thickness times 3.14
    Then Add' 1 material thickness
    .
    So ...... Lets say there is a 1" X 1/4" flat bar that has been rolled and has a diameter of 20".
    Assuming the 1/4" is the thickness, Right ?
    .
    20" (outside dia') minus .250 (1 material thickness) = 19.75 then times Pi (3.14) = 62.046 then plus .250 (1 material thickness) = 62.296
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